Fluid Dynamics and the Navier-Stokes Equations


Contents

Navier-Stokes Equations
Steady Flow
Lift for Aeroplane and Helicopter
High and Low Pressure Cells
Spiral Flow
Hydrostatics
Formation of Spherical Body

Navier-Stokes Equations

Fluid dynamics deals with the motion of liquids and gases, which when studied macroscopically, appear to be continuous in structure. All the variables are considered to be continuous functions of the spatial coordinates and time. The Navier-Stokes equations are a set of nonlinear partial differential equations that describe the flow of fluids. They model weather, the movement of air in the atmosphere, ocean currents, water flow in a pipe, as well as many other fluid flow phenomena. The Navier-Stokes equations for irrotational flow, i.e., for x u = = 0, are:

where u = velocity vector field, = thermodynamic internal energy, p = pressure, T = temperature, = density,
= viscosity, KH = heat conduction coefficient, F = external force per unit mass, , and .

The Navier-Stokes equations are time-dependent and consist of a continuity equation for conservation of mass, three conservation of momentum equations and a conservation of energy equation. There are four independent variables in the equation - the x, y, and z spatial coordinates, and the time t; six dependent variables - the pressure p, density , temperature T, and three components of the velocity vector u. Together with the equation of state such as the ideal gas law - p V = n R T, the six equations are just enough to determine the six dependent variables. In general, all of the dependent variables are functions of all four independent variables. Usually, the Navier-Stokes equations are too complicated to be solved in a closed form. However, in some special cases the equations can be simplified and may admit analytical solutions (see "Differential Equation" for a very brief introduction).

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Steady Flow

The steady flow in a pipe is a very simple solvable case. Since the left-hand side of Eq.(2) vanishes for steady flow, and there is no external force, it can be written in cylindrical coordinates (Figure 03a) as:
Cylinderical Coordinates 0 = - dp / dz + (1/r) d (r d v / dr) / dr ---------- (4)

where v denotes the velocity field in the z direction as shown in Figure 02. For a constant pressure drop (per unit length)
d p / dz is a negative constant, the solution becomes:

v (r) = vm ( 1 - r2 / R2 ) ---------- (5)

where vm = (R2 / 4 ) (- dp / dz) ---------- (6)

Figure 03a Cylindrical Co- ordinates [view large image]

is the velocity at the centre, and R is the radius of the pipe. The boundary conditions are
v = vm at r = 0 and v = 0 at r = R.

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Lift for Aeroplane and Helicopter

The lifting force for aeroplane can be derived straight from Eq.(2) of the Navier-Stokes Equations with the condition for irrotational flow. The resulting formula can be reduced to a very simple form if we assume that the air flow velocity in the z-direction uz is much smaller than that in the x-direction ux (uy = 0 for this particular choice of coordinates):

ux [d(ux)/dz] = - (1/) dp/dz ---------- (10)

Integrating Eq.(10) yields:

{ [(ux1)2 - (ux2)2]} / 2 = (p2 - p1) ---------- (11)

Aeroplane where the subscripts 1 and 2 respectively denote the flow velocity ux, and the pressure p to the upper and lower layers of the air flow. It shows that if the structure of the wings are designed to create a higher flow velocity in the upper layer, then a net pressure in the

Figure 05 Lift for Aeroplane
[view large image]

upward direction is created to lift the aeroplane up into the air provided such force can overcome the weight [see Figure 05, the length of the arrows is proportional to the magnitude of ux (blue) and p (red)]. The force to lift up the plane is just f = P x Sref ,
Ref. Area & Lift Coeff where P = p2 - p1 is the net upward pressure, and Sref (Reference Area) is the effective area acted upon by P. Figure 06 shows the Sref for an aircraft and a helicopter. The actual force F on these objects is determined further by the formula F = f x CL, where CL is the Coefficient of Lift. It depends on the type of aircraft as shown in Figure 06, where the angle of attack is

Figure 06 Ref. Area & Lift Coeff. [view large image]

defined as the angle between the wing and the direction of the airstream. Most aircrafts will behave similarly to the Cessna 172 while high-speed planes with short wingspans, like fighters, will more closely resemble the Lightning data.
Helicopter The lift for helicopter can be derived from Eq.(2) of the Navier-Stokes Equations in a similar way (as for the aeroplane) with the role of ux and uz interchanged because the airflow pattern is different (see Figure 07). Thus for uz >> ux , Eq.(10) becomes:

uz [d(uz)/dz] = - (1/) dp/dz ---------- (12)

Integrating Eq.(12) yields:

{ [(-uz2)2 - (-uz1)2]} / 2 = (p2 - p1) ---------- (13)

Figure 07 Helicopter Airflow [view large image]

where uz is negative as it is pointing toward the negative z direction. It has a form similar to Eq.(11) for the aeroplane. Computation for the lifting force follows exactly the same line as developed previously.
Helicopter In stationary position, the helicopter's engine provides only the lifting force. According to the principle of angular momentum conservation, the body would turn in the opposite direction of the rotating blades. To stabilize the helicopter, a tail rotate is installed to counteract this trend. By applying more or less pitch angle to the tail rotor blades, it can

Figure 08 Helicopter
[view large image]

also be used to make the helicopter turn left or right. Forward motion is achieved by tilting the spinning rotor in the direction of the flight (see Figure 08). There are many factors related to the rotor blades to limit the maximum speed of a helicopter at about 400 km/h.
Propeller By rotating the rotor blades and the z-axis 90o, Eq. (13) is applicable to calculate the forward pressure (or thrust) of a propeller on a ship or airplane (Figure 09). Since the density for water is about 1000 times higher than air, the formula shows that the propeller can generate more thrust with lower flow speed on a ship or boat. It also explains why the prop plane cannot fly high up into the rare atmosphere, where the air density is very low.

Figure 09 A Prop Plane [view large image]

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High and Low Pressure Cells

When cool air mass roams over a warm surface of the Earth, it sinks downward as shown in Figure 10. There is a temporary build-up of air at the central core before it can flow away. The congestion increases the air density and results in a
High Pressure Ridge Low Pressure Cell relatively high, central-pressure zone. As the air diverges from the central region, it is deflected by the Coriolis force in a clockwise circulation (Figures 10 & 12). Thus, most Highs are generally elliptical in shape following their formation. But as they interact with other air masses and topography, and are distorted by forces of the upper atmosphere, high pressure cells often become long and

Figure 10 High Pressure Ridge

Figure 11 Low Pressure Cell
[view large image]

narrow in shape, and is referred to as high pressure ridge in the weather map. Since the air at high altitude is dry, the High is usually associated with fair weather.
At the hot spots on the Earth's surface, warm air rises up triggering surface air to rush in toward the core (Figure 11). The Coriolis force now deflects the converging air in a counter clockwise circulation. Thus, a Low will develop when there is not enough infalling air to replace the rising air at the center. The rising air eventually dissipates at high altitude as high level wind or returning to the surface in cyclic motion. When the circular region of low pressure elongates to a long and narrow band, it is referred to as a low pressure trough. Since the warm air contains lot of moisture, Lows are usually associated the stormy weather as the vapor condensed at upper level. Low pressure cells that travel long distances across the Earth are called cyclones. In extreme cases over warm tropical waters, they become hurricanes or typhoons.

Coriolis Force Mathematically, the sinking and rising air can be explained by Archimedes' principle as discussed in the section of Hydrostatics. Cooler air mass will sink as it is denser than the surrounding air, and vice versa for the warmer air mass. The swirling motion of air on the horizontal plane is determined by the Navier-Stokes Equations in Eq.(2). Since the radial velocity ur is usually much smaller than the circular velocity v = r u in the core region, the radial component of the equation (in cylindrical coordinates) can be reduced to:

Figure 12 Coriolis Force
[view large image]

2 v sin = (1/)p/r ---------- (14a)

where is the angular velocity of the Earth's rotation, and is the angle of the latitude (Figure 12). Eq.(14a) shows that for the low pressure cell, the Coriolis force on the left-hand side is balanced by the pressure gradient force on the right-hand side, and the air circulates in the counter-clock wise direction as depicted in Figure 11. When the radial velocity diverges from the center as for the case of high pressure cell, both forces change sign leaving the equation in exactly the same form with the circular velocity moving in clock wise direction.

If we further assume that the pressure p does not depend on , and v does not depend on z, then the circular component of Eq.(2) (in cylindrical coordinates) can be simplified to:

(v/r) (v/) = - 2 ur sin ---------- (14b)

which shows that another component of the Coriolis force bumps up the circular velocity in a counter-clock wise direction if the air is moving inward, but in a clock wise direction when the radial flow is reversed. Since = 0 at the equator, the effect of the Coriolis force vanishes there as shown in both Eqs.(14a) and (14b).

Red Spot The Great Red Spot (Figure 13) in Jupiter provides a very good example to illustrate the Coriolis force at work. It is a high pressure cell located 22o South of the equator. Thus, the rotational vector is pointing inward to the center (instead of pointing outward as for the case in the Northern hemisphere), and the swirling gas is circulating counter-clock wise. This system of anticyclonic storm has existed for up to 400 years. The long lifetime cannot be attributed entirely to the higher rotational speed (about twice as much as that for the Earth), and hence the stronger Coriolis force. It is suggested that the lack of solid surface to

Figure 13 Great Red Spot
[view large image]

provide friction may play a part contrary to the hurricane on Earth, which always break up shortly after landfall. Note that the oval shape is caused by the constriction from the neighboring cloud bands.

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Spiral Flow

A spiral is usually developed when there is not enough force to oppose the inward movement. This kind of pattern includes
Spiral Galaxy Spiral Hurricane phenomena such as spiral galaxy, hurricane, and drain in the sink (Figures 14, and 15). By neglecting the thickness of the spiral flow, Eq.(2) of the Navier-Stokes Equations in cylindrical coordinates can be expressed in the form:
ur (ur/r) + u (ur/) = Fr ---------- (15a)
ur [(r u)/r] + u [(r u)/] = 0 ---------- (15b)
where we have assumed further that the force acts on the fluid

Figure 14 Barred Spiral Galaxy
[view large image]

Figure 15 Hurricane
[view large image]


only in the radial direction. In addition by assuming constant density for the fluid, Eq.(1) of the continuity equation becomes:
(1/r) [(r ur)/r] + (1/r) [(r u)/] = 0 ---------- (16)
Archimedian Spiral A relationship between the velocity components is obtained by substituting Eq.(16) to
Eq.(15b):
ur = b u ---------- (17)
where b is a constant having the dimension of length. This formula can be integrated once more to yield:
r = a + b ---------- (18)

Figure 16 Archimedean Spiral
[view large image]

where a is another constants of integration. Eq.(18) expresses the trajectory of an Archimedean spiral (see curve on the left of Figure 16). So far there is no restriction on whether the movement is to plunge inward or to expand.
    The appearance of the spiral is determined by the constants of integration:
  1. The value of b determines the winding of the spiral. As b = dr/d is the relative rate of change between r and , a small value of b makes the winding very tight and vice versa.
  2. The solution also admits another spiral arm with - or 180o out of phase (see curves on the right of Figure 16).
  3. With variation of orientation at r 0, the spiral assumes a broad sweeping pattern much like the hurricane in Figure 15 instead of one slim locus.
  4. The sign of b, i.e., b > 0 or b < 0, has the effect on the winding direction - whether it turns to the left or right.
  5. For the barred spiral like the Milkyway in Figure 14, the constant a > 0, while a = 0 is for the case of true spiral galaxy such as NGC2997. It turns out that the formation of spiral arms in galaxy is more complicated than this simple minded approach, which would produce tightly wound spirals (within 500 million years) in contrary to observation (see more in Theory of Spiral Arm Formation).
By substituting Eqs.(15b), (17) into Eq.(15a), it is found that the radial component of the velocity depends on r as:
ur2 / r = Fr ---------- (19a).
On the disk of the spiral galaxy Fr = GM / r2 + GM' / r2 - r2u2 / r
Rotation Curve with M to be the mass of the central black hole, while the mass on the disk within r is given by M' = 2 r dr, where = 0 (r0/r) is the surface density in unit of gm/cm2, 0 is its cutoff value at the edge of the galaxy r = r0, and the third term is the centrifugal force. Thus, the radial and rotational components of the velocity can be expressed as:
ur2 = GM / r + 2G0r0 - r2u2 ---------- (19b),
r2u2 = r (GM + 2G 0r0 r) / (b2 + r2) ---------- (19c),

Figure 17a Rotation Curve for Milky Way [view large image]

which has the same profile of the rotation curve for the disk as shown in Figure 17a with a peak at rm (40r0b/M) b for 40r0b >> M. The observed curve takes into account of the dark matter in the halo.
According to the currently available data on the Milkyway:
2r020 1011Msun,
M 3x106Msun,
r0 30 kpc,
rm 0.5 kpc,
the followings can be derived:
b 0.015 kpc, which implies tightly wound arms, and
(40r0b/M) 33 - enough to qualify for a peak in the rotation curve.
The calculated rotation and radial velocities at r0 are: r0 u 122 km/sec, and ur 0.06 km/sec respectively.
At the event horizon of the central black hole rs 2GM/c2 matter plunging into the hole with radial velocity ur c / 21/2 (where c is the velocity of light), but the rotation velocity reduces to rsu 4 km/sec.
To check the winding of the Milkyway spiral arms, it is noticed that the rotation velocity is in the order of 100 km/sec for a wide range of distance outside the core. Following this simplification, the spiral arms wind through a cycle of 360o in about 600 million years. Thus, it can be estimated from Eq.(17) that the change in the radial position of the arm is about 0.1 kpc. The observed separation of the arm from = 0 to 2 as shown in Figure 14 is about 20 kpc. This is obvious a contradiction, and that's why the simple spiral flow in galaxy from fluid dynamics consideration alone is at best a toy model as mentioned earlier.

The derivation is a little bit more involved for the hurricane. The attractive force Fr is replaced by the pressure gradient
Pressure Gradient dp/dr (which has overwhelmed the Coriolis and centrifugal forces in this case):
ur2 / r = (1/) dp/dr ---------- (20).
The dependence of p on r is shown in Figure 17b. The observational data (for the "Charlie" type hurricane) can be approximated by the empirical formula:
p = p0 [5.5 - e-k(r - re)] ---------- (21) for r re,
where re is the distance from the center to the wall of the eye (Figure 17b), p0 = 220 mb and k is a constant related to the steepness of the pressure gradient. Thus, the pressure gradient is:
dp/dr = kp0e-k(r - re) ---------- (22) for r re
or
ur2 = (krp0/) e-k(r - re) ---------- (23) for r re.
At the wall of the eye, r = re, and ur2 = krep0/.

Figure 17b Pressure Gradient of Hurricane

The rotation curve is given by r2u2 = (kr3p0/b2) e-k(r - re), which reproduces a profile similar to the curve in Figure 17b with a maximum at rm = 3/k.
This kind of analysis is also applicable to the drain in the sink although on a much smaller scale.
Figure 17b offers a rough estimate of:
rm 40 km,
re 10 km,
and ur/(reu) 2 at re.
The followings can be derived from these data:
k = 3/rm 0.075 km-1,
b = [ur/(reu)] re 20 km.
Thus the radial distance changes by about 125 km covering about 2/3 of the average hurricane size when turns one cycle. There is no tightly wound arms. This model seems to represent the actual system quite well. Meanwhile, the calculated radial and circular velocities at the wall of the eye are ur 4.6 m/h and reu 2.3 m/h respectively indicating a calm region there.

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Hydrostatics

Hydrostatics Atmosphere The term "hydrostatics" is applied to the study of fluids at rest, including both liquids and gases. For this special case, u = 0 in the Navier-Stokes equations, the external force F = -g (in the negative y direction) and the pressure gradient is just dp. Eq.(2) is reduced to the simple form:

dp = - g dy ---------- (24).

Taking point 1 and 2 as shown in Figure 18, integration of
Eq.(24) yields:

p2 - p1 = - g (y2 - y1) ---------- (25)

Figure 18 Hydrostatics
[view normal image]

Figure 19 Atmosphere [view large image]

which shows that the pressure is less in higher elevation as it is well known in the Earth's atmosphere (Figure 19).

Archimedes' principle states that a body immersed in a fluid is buoyed up by a force equal to the weight of the displaced fluid. Independent of shape and composition, objects of equal volume experience equal buoyant forces. Just for illustration purpose, let us consider a rectangular block of water with height h and area A (perpendicular to page) on the top and bottom faces (the grey stripe in Figure 18). The pressure on the sides will cancel out leaving only a net force to balance exactly the weight of the water block. Mathematically, since the pressure p = f / A, where f is the force exerted on A, Eq.(25) can be rewritten as:

F = f1 - f2 = V g ---------- (26)

where V = h A is the volume of the water block, and F is the buoyant force.

An object will float or sink in the water depending on whether its weight Mg is smaller or greater than the buoyant force.

Submarine Submarine controls the submerging and surfacing by admitting water into a tank or pumping it out. When the submarine is on the surface its ballast tanks are full of air (Figure 20). The air inside the hull brings the average density of the entire ship below the density of saltwater. Because the sub is less dense, it floats. The average density of a submerging submarine is increased by flooding the ballast tanks with water through flood ports on the bottom of the tanks with the release of air out of the top of the tanks (Figure 20). Once the overall density of the submarine is equal to the water around it, it has the neutral buoyancy and will remain at that depth. High pressure air is blown into the ballast tanks to push the water out when the submarine is prepared to surface again.

Figure 20 Submarine
[view large image]

Air does not provide a lot of buoyant force because its density is about 1000 times lower. Only balloon filled with low density gas such as hydrogen or helium can rise up to the sky.

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Formation of Spherical Body

Deformation of Solid Body Geometric Shape Solid body does not flow like fluid, the Navier-Stokes Equations doesn't seem to be applicable in such case. However, the equation can be used to calculate the critical mass for the self-gravity of a solid body to overcome its resistant forces so that it assumes a hydrostatic equilibrium (nearly round) shape. Solid

Figure 21 Deformation of Solid Body

Figure 22 Geometric Shape [view large image]

body actually has elastic property, that makes it to deform in response to the external force as shown by the deformation of the moon by the gravitational tug of a planet in Figure 21.
Since there is no flow in solid body u 0 in the Navier-Stokes Equation (2), which then becomes:
F = p / ---------- (27).
The external force per unit mass is just the gravitational force (per unit mass):
F = GM / r2 ---------- (28).
The pressure gradient in terms of the spherical coordinate r is:
p = dp / dr = Y / r ---------- (29)
where Y = stress/strain = dp/(dr/r) is the Young's modulus, the value of which ranges from 0.0001 x 1012 dynes/cm2 for rubber to about 12 x 1012 dynes/cm2 for diamond. It lumps all the microscopic forces into one macroscopic measurement.
Substituting Eq.(28) and (29) into Eq.(27) yields:
GM / r2 = Y / r. ---------- (30)

There are 3 possible cases for Eq.(30):
Case 1: GM / r2 Y / r, the solid body does not has enough gravitational pull to overcome the resistance, its geometric shape would be irregular as shown by the Itokawa asteroid in Figure 22.
Case 2: GM / r2 = Y / r, the solid body just has enough gravitational pull to overcome the resistance, its geometric shape would be round as shown by the Earth/Moon in Figure 22.
Case 3: GM / r2 Y / r, the solid body has more than enough gravitational pull to overcome the resistance. The object would shrink until equilibrium is achieved.

Eq.(30) can be simplified further, if we assume uniform distribution of matter: = 4r3/ 3, thus Eq.(30) can be rewritten as:
M = ( (4/3)Y/G)1/2r2 ---------- (31)

Table 01 is a list of solid objects examined under the assumption that Y = 1.0 x 1012 dynes/cm2 (then M 8x109r2) . If the mass M on the left-hand side of Eq.(31) is greater than the value on the right-hand side, the value of Y is then adjusted to maintain equilibrium at the observed radius r.

Object Type Mass M (gm) Radius or Size r (cm) 8x109r2(gm) Adjusted Y (1012dynes/cm2) Geometric Shape
Neutron Star Star 0.2 - 6.0x1033 ~1.0x106 ~8.0x1021 Super-hard Spherical
Mercury Planet 3.6x1026 1.1x108 1.0x1026 13 Spherical
Venus Planet 5.7x1027 5.7x108 2.6x1027 4.8 Spherical
Earth Planet 6.0x1027 6.0x108 2.9x1027 4.0 Spherical
Moon Satellite 7.2x1025 7.8x107 4.9x1025 2.0 Spherical
Mars Planet 6.6x1026 3.0x108 7.2x1026 0.84 Spherical
Pluto Dwarf Planet 1.2x1025 1.2x108 1.2x1026 0.01 Spherical
Phobos Satellite of Mars 1.0x1019 2.7x106 5.8x1022 N/A Irregular
Deimos Satellite of Mars 1.8x1018 1.5x106 1.8x1022 N/A Irregular
Itokawa Asteroid 3x1013 5.4x104 2.4x1019 N/A Irregular
Comet Planetesimal ~6x1015 ~6x104 ~3x1019 N/A Irregular
Human Living Organism ~105 ~2x102 ~3x1014 N/A Definitely not Spherical
Neutron Composite Particle 1.67x10-24 ~10-13 ~8x10-17 N/A Unknown
Electron Elementary Particle 9.1x10-28 ~10-16 ~8x10-23 N/A Unknown

Table 01 Geometric Shape of Solid Body